分析:(1)(4)根據(jù)四則混合運算的運算順序計算即可:先算乘除,再算加減,有括號的要先算括號里面的;
(2)可根據(jù)乘法交換律及結合律計算;
(3)可將99變?yōu)?00-1后根據(jù)乘法分配律計算;
(5)(6)可根據(jù)乘法分配律計算.
解答:解:(1)798+10570÷35
=798+302,
=1100;
(2)
×2.5×
×4
=(
×
)×(2.5×4),
=3×10,
=30;
(3)187×99
=187×(100-1),
=187×100-187×1,
=18700-187,
=18513;
(4)2.5÷[(17.2-4.5×3.6)÷0.04]
=2.5÷[(17.2-16.2)÷0.04],
=2.5÷[1÷0.04],
=2.5÷25,
=0.1;
(5)24×(
-
+
)
=24×
-24×
+24×
,
=16-6+10,
=20;
(6)4.63×75%+6.47×
-0.75.
=4.63×0.75+6.47×0.75-0.75,
=(4.63+6.47-1)×0.75,
=10.1×0.75,
=7.575.
點評:當算式中同時含有分數(shù)、小數(shù)與百分數(shù)時,一般要先將式中數(shù)據(jù)化為統(tǒng)一的數(shù)據(jù)形式后再進行計算.