解:(1)2.5×1.25×32,
=2.5×1.25×8×4,
=(2.5×4)×(1.25×8),
=10×10,
=100;
(2)10.36-3.53-6.47,
=10.36-(3.53+6.47),
=10.36-10,
=0.36;
(3)2.1+2

+1.19+3

,
=(2

+3

)+(2.1+1.19),
=6+3.29,
=9.29;
(4)35×(

),
=35×

+35×

,
=21+10,
=31;
(5)24×[(

)÷

],
=24×[(

)×

],
=24×[

],
=24×

,
=8;
(6)

,
=

÷[

×


],
=

÷[

],
=

÷[

],
=

,
=

,
=2

;
分析:算式(1)中可將32拆分為8×4,然后再據(jù)乘法交換律及結(jié)合律進行計算;
算式(2)可根據(jù)一個數(shù)連續(xù)減去兩個數(shù),可以用這個數(shù)減去這兩個數(shù)的和,使計算更加簡便;
算式(3)可根據(jù)加法的交換律和結(jié)合律計算更加簡便;
算式(4)可根據(jù)乘法分配律進行計算,使計算更加簡便;
算式(5)、(6)根據(jù)四則混合運算的運算順序計算即可.
點評:本題考查了運算定律,運算性質(zhì),四則混合運算等內(nèi)容的掌握運用情況及靈活運用所學(xué)知識的運用情況.