脫式計算. 6.5×8+3.5×8-44 | 8.5+(5.6-4.8)×13 | 1.9-1.9×(1.9-1.9) |
![]() ![]() | 1×![]() ![]() ![]() | ![]() ![]() |
49.5×![]() ![]() | ![]() ![]() ![]() ![]() ![]() | ![]() ![]() ![]() |
897×![]() | [![]() ![]() ![]() ![]() | ![]() ![]() ![]() ![]() ![]() |
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解:
(1)6.5×8+3.5×8-44,
=(6.5+3.5)×8-44,
=10×8-44,
=80-44,
=36;
(2)8.5+(5.6-4.8)×13,
=8.5+0.8×13, =8.5+10.4, =18.9; (3)1.9-1.9×(1.9-1.9), =1.9-1.9×0, =1.9-0, =1.9; (4) ![]() ![]() =( ![]() ![]() =2×29, =58; (5)1× ![]() ![]() ![]() = ![]() ![]() =20× ![]() =2; (6) ![]() ![]() =(101-1)× ![]() =100× ![]() =28; (7)49.5× ![]() ![]() =49.5×10.6-49.5×0.6, =49.5×(10.6-0.6), =49.5×10, =495; (8) ![]() ![]() ![]() ![]() ![]() = ![]() ![]() ![]() ![]() ![]() =( ![]() ![]() ![]() =11× ![]() =7; (9) ![]() ![]() ![]() = ![]() ![]() ![]() = ![]() ![]() = ![]() ![]() = ![]() (10)897× ![]() =897×0.375-0.375+104×0.375, =(897-1+104)×0.375, =1000×0.375, =375; (11)[ ![]() ![]() ![]() ![]() =[ ![]() ![]() ![]() ![]() ![]() =[ ![]() ![]() ![]() ![]() =[ ![]() ![]() ![]() = ![]() ![]() = ![]() (12) ![]() ![]() ![]() ![]() ![]() =(9+99+999+9999)+ ![]() =9+99+999+9999+4, =(9+1)+(99+1)+(999+1)+(9999+1), =10+100+1000+10000, =11110; (13) ![]() ![]() ![]() = ![]() ![]() ![]() =2- ![]() = ![]() |
分析:
(1)先根據(jù)四則混合運算的順序確定應(yīng)該先算什么后算什么:只有一級運算時,從左到右計算;有兩級運算時,先算乘除,后算加減.有一層括號時,先算括號里的;有多層括號時,先算小括號里的. (2)能夠運用簡便算法的題目,根據(jù)所學(xué)定律選擇適合的簡便方法. |
點評:此題主要考察四則混合運算的順序和簡便算法的靈活運用,要根據(jù)每一題的特點選擇適合的方法.
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