分析:算式①可根據(jù)一個數(shù)減兩個數(shù),等于減去這兩個數(shù)的和的減法性質(zhì)及加法交換律進(jìn)行計算;
算式②、③、④、⑥可根據(jù)乘法分配律進(jìn)行計算;
算式⑤根據(jù)四則混合運算的運算順序計算即可,先算乘除,再算加減,有括號的要先算括號里面的.
解答:解:①7.28-3.14+2.72-2.86
=(7.28+2.72)-(3.14+2.86),
=10-6,
=4;
②9
×9.8+9.25×
=9.25×9.8+9.25×0.2,
=(9.8+0.2)×9.25,
=10×9.25,
=92.5;
③48×(
+-)
=48×
+48×
-48×
,
=12+6-4,
=14;
④(
-)×21+
=
×21-
×21+
,
=14-12+
;
=2
;
⑤(
+)÷(
+)
=(
+
)÷(
+
),
=
×
,
=7;
⑥0.7÷[(
-)×24].
=0.7÷[
×24-
×24],
=0.7÷[20-6],
=0.7÷14,
=0.05.
點評:當(dāng)算式中含有分?jǐn)?shù)與小數(shù)時,要根據(jù)算式中數(shù)據(jù)的特點將分?jǐn)?shù)化為小數(shù)或?qū)⑿?shù)化為分?jǐn)?shù)后再計算.