解:各物質(zhì)均由短周期元素組成,A為淡黃色固體,B為常見的無色液體,則A為Na
2O
2,B為H
2O,D、F、G為單質(zhì),由轉(zhuǎn)化關(guān)系圖可知,D為氧氣,G為Al,F(xiàn)為氫氣,
(1)A為Na
2O
2,其電子式為
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,B為H
2O,其電子式為
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,
故答案為:
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;
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;
(2)轉(zhuǎn)化中①為過氧化鈉與水的反應(yīng),該反應(yīng)為2Na
2O
2+2H
2O=4NaOH+O
2↑,反應(yīng)②為Al與NaOH溶液的反應(yīng),該反應(yīng)為2Al+2NaOH+2H
2O=2Al+2NaOH+3H
2↑,
故答案為:2Na
2O
2+2H
2O=4NaOH+O
2↑;2Al+2NaOH+2H
2O=2Al+2NaOH+3H
2↑;
(3)D為氧氣,G為Al,與海水構(gòu)成的原電池中Al作負(fù)極,負(fù)極反應(yīng)式為Al-3e
-=Al
3+,故答案為:Al-3e
-=Al
3+.
分析:各物質(zhì)均由短周期元素組成,A為淡黃色固體,B為常見的無色液體,則A為Na
2O
2,B為H
2O,D、F、G為單質(zhì),由轉(zhuǎn)化關(guān)系圖可知,D為氧氣,G為Al,F(xiàn)為氫氣,然后結(jié)合物質(zhì)的性質(zhì)及化學(xué)用語來解答.
點(diǎn)評:本題考查無機(jī)物的推斷,明確淡黃色物質(zhì)及與水反應(yīng)生成氧氣是解答本題的關(guān)鍵,并注意化學(xué)用語的規(guī)范應(yīng)用,題目難度不大.