分析:(1)先將除法變?yōu)槌朔,再根?jù)乘法分配律進(jìn)行計(jì)算;
(2)先乘方和去括號(hào),再根據(jù)有理數(shù)的加減法進(jìn)行計(jì)算;
(3)利用加法交換律把同分母結(jié)合在一起進(jìn)行計(jì)算;
(4)先去絕對(duì)值,計(jì)算括號(hào)里面的和乘方運(yùn)算,再進(jìn)行乘除運(yùn)算;
(5)先計(jì)算乘方、乘法括號(hào)里面的計(jì)算,再進(jìn)行加減計(jì)算就可以得出結(jié)論.
解答:解:(1)原式=(-
-
+
)×36
=
-×36-×36+×36=-27-20+21
=-26;
(2)原式=-2+3-1
=0;
(3)原式=
+2-2-3=3-6
=-3;
(4)原式=
÷×16=
××16=
;
(5)原式=-1-(-
)×
+(-8)×
=-1-(-2)-
=-1+2-
=
.
點(diǎn)評(píng):本題考查了有理數(shù)的乘方運(yùn)算,乘除法運(yùn)算,加減運(yùn)算.在解答時(shí)要注意在運(yùn)算的過中確定結(jié)果的符號(hào).嚴(yán)格按照運(yùn)算順序進(jìn)行.