在△ABC中,∠C=90°,AC=12,BC=5,則sinA=________,cosA=________,sinB=________,cosB=________.
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分析:先運(yùn)用勾股定理求得AB的長(zhǎng)度,然后根據(jù)三角函數(shù)的定義求解.
解答:在△ABC中,
∵∠C=90°,AC=12,BC=5,
∴AB=
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=13,
則sinA=
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=
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,
cosA=
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=
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,
sinB=
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=
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,
cosB=
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=
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.
故答案為:
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,
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,
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,
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.
點(diǎn)評(píng):本題考查了銳角三角函數(shù)的定義以及勾股定理,屬于基礎(chǔ)題,掌握三角函數(shù)的定義是解題的關(guān)鍵.