小題1:(1)解:設該專營店第一季度購進A、B兩種型號手機的數量分別為x部和y部. 1分
由題意可知:·························································· 3分
解得:
答:該專營店本次購進A、B兩種型號手機的數分別為15部和18部.····················· 4分
小題2:(2)解:設第二季度購進A型號手機a部.········································ 5分
由題意可知:1200a+1000(34-a)≤36000,····················································· 6分
解得:a≤10··························································································· 7分
不等式的最大整數解為10
答:第二季度最多能購A型號手機10部.······················································· 8分