解:(1)由題意得,拋物線頂點是(3,2),
設拋物線解析式為:y=a(x-3)
2+2,
把點(0,1.4)代入得:1.4=9a+2,
解得:a=-
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,
∴拋物線解析式為:y=-
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(x-3)
2+2;
(2)當y=0時,0=-
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(x-3)
2+2,
解得,x
1=4-
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(舍去),x
2=4+
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,
即此次實心球被推出的水平距離OC為(4+
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)m.
分析:(1)已知拋物線經(jīng)過頂點(3,2),y軸上一點(0,1.4),可設拋物線頂點式,代入求解析式;
(2)當y=0時,求得x的值,即為實心球被推出的水平距離OC.
點評:本題考查了待定系數(shù)法求二次函數(shù)的解析式的運用,根據(jù)函數(shù)值求自變量的值的運用,解答時求出函數(shù)的解析式是關(guān)鍵.