B
分析:根據(jù)一氧化碳的化學(xué)式可求出其中氧元素的質(zhì)量分?jǐn)?shù)為:
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×100%=57.1%,故雜質(zhì)中氣體中的氧元素的質(zhì)量分?jǐn)?shù)至少有一種要小于57%進(jìn)行分析.
解答:二氧化碳中氧元素的質(zhì)量分?jǐn)?shù)=
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×100%=72.8%
一氧化氮中氧元素的質(zhì)量分?jǐn)?shù)=
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×100%=53.3%
二氧化氮中氧元素的質(zhì)量分?jǐn)?shù)=
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×100%=69.6%
氮?dú)庵袥]有氧元素,故氧元素的質(zhì)量分?jǐn)?shù)為0;
A、②③組合中一氧化氮的氧元素質(zhì)量分?jǐn)?shù)為53.3%,小于57%;故可能為雜質(zhì);
B、①③組合中二氧化碳和二氧化氮中氧元素的質(zhì)量分?jǐn)?shù)都大于57%;故不能為雜質(zhì);
C、①④組合中氮?dú)獾难踉氐馁|(zhì)量分?jǐn)?shù)為0,小于57%;故可能為雜質(zhì);
D、②④組合中二者的氧元素質(zhì)量分?jǐn)?shù)都小于57%,故可能為雜質(zhì);
故選B
點(diǎn)評:本題主要考查了元素質(zhì)量分?jǐn)?shù)的計(jì)算,元素的質(zhì)量分?jǐn)?shù)=
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×100%.